/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* mergeLists(ListNode *l1, ListNode *l2)
{
// ref to problem 22, merge two sorted list
if (NULL == l1) return l2;
if (NULL == l2) return l1;
if (l1->val < l2->val) {
l1->next = mergeLists(l1->next, l2);
return l1;
} else {
l2->next = mergeLists(l1, l2->next);
return l2;
}
}
ListNode* mergeKLists(vector& lists) {
// merge 2 by 2 lists
size_t iters = lists.size() / 2;
while (iters > 0) {
iters = lists.size() / 2;
for (size_t i = 0; i < iters; i++){
lists[i] = mergeLists(lists[i], lists[lists.size() - 1 - i]);
}
lists.erase(lists.begin() + iters + (1 == lists.size() % 2), lists.end());
}
return (lists.size() > 0) ? lists[0] : NULL;
}
};
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